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9 sec^(2) A - 9 tan^(2) A =...

`9 sec^(2) A - 9 tan^(2) A` =

A

0

B

3

C

-9

D

9

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \(9 \sec^2 A - 9 \tan^2 A\), we can follow these steps: ### Step-by-Step Solution: 1. **Factor out the common term:** \[ 9 \sec^2 A - 9 \tan^2 A = 9 (\sec^2 A - \tan^2 A) \] 2. **Use the trigonometric identity:** We know the identity: \[ \sec^2 A - \tan^2 A = 1 \] Therefore, we can substitute this identity into our expression: \[ 9 (\sec^2 A - \tan^2 A) = 9 \cdot 1 \] 3. **Simplify the expression:** \[ 9 \cdot 1 = 9 \] ### Final Answer: \[ 9 \sec^2 A - 9 \tan^2 A = 9 \] ---
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TARGET PUBLICATION-TRIGONOMETRY -Chapter Assessment
  1. cot 60^(@) =

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  2. tantheta . Cot theta =

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  3. When we see at a lower level , from the horizontal line , angle formed...

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  4. 9 sec^(2) A - 9 tan^(2) A =

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  5. If the distance of a point from the tower is equal to the height of th...

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  6. If cosec theta = (13)/(12) , then find the values of cot theta and sin...

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  7. Prove the identity sin^(2)theta + cos^(2) theta = 1 with the help of g...

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  8. A person standing at a distance of 90 m from a church observes the ang...

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  9. (tantheta + sintheta)/(tantheta - sintheta) =(sectheta + 1 )/ (secthe...

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  10. If cos theta + (1)/(cos theta) = 4 , then prove that cos^(2) theta + ...

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  11. Prove the following: sec^6 x - tan^6 x = 1 + 3sec^2 x xx tan^2x

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  12. A tree breaks due to storm and the broken part bends, so that the top ...

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  13. Two buildings are in front of each other on a road of width 15 meters....

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  14. If tan theta = 1, then find the value of (sin theta + cos theta)/(sec ...

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  15. A straight highway leads to the foot of a tower. A man standing at ...

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  16. If sin theta+tan theta =P then prove that (p^2-1)/(p^2+1)=sin theta

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  17. If 3 tan^(2)theta - 4sqrt(3)tan theta + 3 = 0, find the acute angle th...

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  18. Eliminate theta if x=a cot theta -b cosec theta and y=acot theta+b cos...

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