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In the adjoining figure, BC is a diamete...

In the adjoining figure, BC is a diameter of the circle with centre M. PA is a tangent at A from P, which is a point on line BC. AD `bot` BC
prove that `DP^(2)=BPxxCP-BDxxCD`

Answer

Step by step text solution for In the adjoining figure, BC is a diameter of the circle with centre M. PA is a tangent at A from P, which is a point on line BC. AD bot BC prove that DP^(2)=BPxxCP-BDxxCD by MATHS experts to help you in doubts & scoring excellent marks in Class 10 exams.

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Knowledge Check

  • In the given figure, AB and AC are tangents to the circle with centre O. Given that angle BAC = 70^(@) and P is a point on the minor are BC, find angle BPC.

    A
    `110^(@)`
    B
    `140^(@)`
    C
    `125^(@)`
    D
    `136^(@)`

  • In the given circle O is the centre of the circle and AD, AE are the two tangents. BC is also a tangent, then:

    A
    `AC+AB=BC`
    B
    `3AE=AB+BC+AC`
    C
    `AB+BC+AC=4AE`
    D
    `2AE=AB+BC+AC`

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