Find the value of a, b and c for the following quadratic equations by comparing with general form :
`6x^(2)-13x+6=0`

Answer

To find the values of \( a \), \( b \), and \( c \) for the quadratic equation \( 6x^2 - 13x + 6 = 0 \), we will compare it with the general form of a quadratic equation, which is given by:

\[ Ax^2 + Bx + C = 0 \]

### Step-by-Step Solution:

1. **Identify the general form of a quadratic equation**:
The general form is \( Ax^2 + Bx + C = 0 \).

2. **Write down the given quadratic equation**:
The given equation is \( 6x^2 - 13x + 6 = 0 \).

3. **Compare coefficients**:
- The coefficient of \( x^2 \) (which corresponds to \( A \)) is \( 6 \).
- The coefficient of \( x \) (which corresponds to \( B \)) is \( -13 \).
- The constant term (which corresponds to \( C \)) is \( 6 \).

4. **Assign values to \( a \), \( b \), and \( c \)**:
- From the comparison, we have:
- \( a = 6 \)
- \( b = -13 \)
- \( c = 6 \)

### Final Values:
- \( a = 6 \)
- \( b = -13 \)
- \( c = 6 \)