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Solve the following quadratic equations ...

Solve the following quadratic equations by factorisation method:
`2y^(2)+27+13=0`

Text Solution

Verified by Experts

The correct Answer is:
`-13, -(1)/(2)` are the roots of the given quadratic equation.
`2y^(2)+27y+13=0" "2xx13=26`
`:.2y^(2)+26y+y+13=0" "26=1`
`:.2y(y+13)+1(y+13)=0`
`:.(y+13(2y+1)=0`
`:.y+13=0or2y+1=0`
`:.y=-13or2=-1`
`:.y=-(1)/(2)`
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