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Complete the following activity to sovle...

Complete the following activity to sovle the quadratic equation by factorisation method : `3x^(2)-2sqrt6x+2=0`

Text Solution

Verified by Experts

The correct Answer is:
`(sqrt2)/(sqrt3),(sqrt2)/(sqrt3)` are the roots of the given quadratic equation.
`3x^(2)-2sqrt6x+2=0" "3xx2=6`
`:.3x^(2)-sqrt6x-sqrt6x+2=0" "-sqrt6-sqrt6`
`:.3x^(2)-sqrt3xxsqrt2-sqrt3xxsqrt3x-sqrt2=0`
`:.sqrt3(sqrt3x-sqrt2)-sqrt2(sqrt3x-sqrt2)=0`
`:.(sqrt3x-sqrt2)(sqrt3x-sqrt2)=0`
`:.sqrt3x-sqrt2=0orsqrt3x-sqrt2=0`
i.e., `sqrt3x=sqrt2" ":.x=(sqrt2)/(sqrt3)`
Here, both the roots are the same.
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