Solve the following quatratic equations by completing square method :
`x^(2)+2x-5=0`

Answer

`-1-sqrt6,-1+sqrt6` are the roots of the given quadratic equation.

Explanation

`x^(2)+2x-5=0`
Comparing `x^(2)+2x" with "x^(2)+2xy,`
`2xy=2x:.y=1:.y^(2)=1`
`:.x^(2)+2x+1` is a perfect square trinomial.
`x^(2)+2x-5=0`
`:.x^(2)+2x+1-1-5=0`
`:.(x+1)^(2)-6=0`
`:.(x+1)^(2)-(sqrt6)^(2)=0`
`:.(x+1+sqrt6)(x+1-sqrt6)=0`
`:.x+1+sqrt6=0orx+1-sqrt6=0`
`:.x=-sqrt6orx=-1+sqrt6`