Mr. Kasam runs a small business of making earthen pots. He makes certain number of pots on daily basis. Production cost of each pot is Rs. 40 more than 10 times total number of pots, he makes in one day. If production cost of all pots per day is Rs. 600, find production cost of one pot and number of pots he makes per day.

Answer

He makes 6 earthen pots per day and the cost of each earthen pot is RS 100.

Explanation

Let Kasam make x earthen pots per day. Then the cost of each earthen pot is RS(10x+40). From the given condition,
`x(10x+40)=600`
`:.10x^(2)+40x-600=0`
`:.x^(2)+4x-60=0" "` ….. (Dividing by 10 )
`:.x^(2)+10x-6x-60=0`
`:.x(x+10)-6(x+10)=0`
`:.(x+10)(x-6)=0`
`:.x+10=0orx-6=0`
`:.x=-10orx=6`
But the number of earthen post cannot be negative.
`:.x=-10` is unacceptable.
`:.x=6`
The cost of each earthen pot =10x+40
`=10(6)+40=60+40=100`