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A frequency distribution table for the p...

A frequency distribution table for the production of oranges of some farm owners is given below.
Find the mean production of oranges by ' assumed mean ' method .

Text Solution

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The correct Answer is:
The mean of production of oranges is Rs. `35,310`.

Let us take `37.5` as the assumed mean. Them `A = 37.5` and deviation `d_(i) = x_(i) - A = x_(i) - 37.5`

Here, `Sigmaf_(i)d_(i) = - 175, Sigmaf_(i) = 80`
` bard = (Sigmaf_(i)d_(i))/(Sigmaf_(i)) = (-175)/80 = - 2.1875 approx - 2.19`
Mean ` barX = A + bard`
` = 37.5 + (-2.19)`
` = 37.5 - 2.19 = 35.31` thousands = 35310.
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