Find the magnitude of the acceleration due to gravity at the surface of the earth. ( M ` = 6 xx 10^(24) ` Kg, R = 6400 Km)

Explanation

Data : `M=6xx10^(24)kg,`
`R=6400km=6.4xx10^(6)m,`
`G=6.67xx10^(-11)N.m^(2)//kg^(2), g=?`
`g=(GM)/(R^(2))`
`=(6.67xx10^(-11)N.m^(2)//kg^(2)xx6xx10^(24)kg)/((6.4xx10^(6)m)^(2))`
`=(66.7xx6)/((6.4)^(2))m//s^(2)=9.77m//s^(2)`
The magnitude of the acceleration due to gravity at the surface of the earth `=9.77m//s^(2)`.