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The bob of a pendulum of mass 8 mu g car...

The bob of a pendulum of mass `8 mu g` carries an electric charge of `39.2xx10^(-10)` coulomb in an electric field of `20xx10^(3)` volt/meter and it is at rest. The angle made by the pendulum with the vertical will be

A

`27^(@)`

B

`45^(@)`

C

`87^(@)`

D

`127^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B
`T sin theta= qE, T cos theta= mg`

`:. tan theta= (qE)/(mg)= (39.2xx10^(-10)xx20xx10^(3))/(8xx10^(-6)xx9.8)=1`
`implies theta= 45^(@)`
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