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The locus of the points (in the xy-plane...

The locus of the points (in the `xy`-plane) where the electric field due to a dipole (dipole axis is along `x`-axis and its equatorial is along `y`-axis) is perpendicular to its axis, is

A

straight line perpendicular to the axis

B

circle

C

Parabola

D

straight line having inclination `theta= tan^(-1)sqrt(2)` with the axis.

Text Solution

Verified by Experts

The correct Answer is:
D
For the given point
`theta+alpha= pi//2implies alpha= pi//2-theta`

As `tan alpha= (tan theta)/(2)`
`implies tan((pi)/(2)-theta)= (tan theta)/(2)implies tan theta= sqrt(2)`
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Knowledge Check

  • An electric dipole is placed along x -axis with its centre at origin:

    A
    The electric field is perpendicular to each and every point on `y-z` plane
    B
    `y-z` plane is an equipotential surface
    C
    `y-z` plane is not equipotential surface
    D
    Flux of electrix field enclosing dipole is zero

  • The ratio of the electric field due to an electric dipole on its axis and on the perpendicular bisector of the dipole is -

    A
    `1:2`
    B
    `2:1`
    C
    `1:4`
    D
    `4:1`

  • If E_(a) be the electric field intensity due to a short dipole at a point on the axis and E_(r) , be that on the perpendicular bisector at the same distance from the dipole, then

    A
    `E_(a)=E_(r)`
    B
    `E_(a)=2E_(r)`
    C
    `E_(r)=2E_(a)`
    D
    `E_(a)=sqrt(2E_(r))`

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