The point charges `Q` and `-2Q` are placed at some distance apart. If the electirc field at the location of `Q` is `E`, the electric field at the location of `-2Q` will be

Options

A. `-(3E)/(2)`
B. `-(E )/(2)`
C. `-E`
D. `-2E`

Answer

B

Explanation

The intensity of electric field at a point due to charges `Q`, distance `r` is given by
`E= (1)/(4piepsilon_(0)) ((-2Q))/(r )`….(i)
Also `E'=(1)/(4piepsilon_(0))((Q))/(r )`…(2)
Dividing EQ.(1) by Eq.(2), we get
`(E )/(E' )=-(2Q)/(Q) implies E'= -(E)/(2)`