Two infinitely long parallel conducting plates having surface charge densities `+ sigma` and `-sigma` respectively, are seperated by a small distance. The medium between the plates is vacuum. If `epsilon_(0)` is the dielectric permittivity of vacumm, then the electric field in the region between the plates is

Options

A. `0 "volts"//meter`
B. `(sigma)/(2epsilon_(0))"volts"//meter`
C. `(sigma)/(epsilon_(0))"volts"//meter`
D. `(2sigma)/(epsilon_(0))"volts"//meter`

Answer

C

Explanation

Given that couducting plates have surface charge densities `+sigma` and `-sigma` respectively. Since the sheet is large, the electric field `E` at energy point near the sheet will be perpendicular to the sheet.

If `sigma` is surface charge density then, electric field between the plates is
`= (sigma)/(2 epsilon_(0))+(sigma)/(2 epsilon_(0))`
`=(sigma)/(epsilon_(0)) "volts"//"meter"`