Home
Class 12
PHYSICS
The radius of nucleus of sliver (atomic ...

The radius of nucleus of sliver (atomic number `= 47`) is `3.4 xx 10^(-14)m`. The electric potential on the surface of uncleus is `(e = 1.6 xx 10^(-19) C)`

A

`1.99 xx 10^(6)` volt

B

`2.9 xx 10^(6)` volt

C

`4.99 xx 10^(6)` volt

D

`0.99 xx 10^(6)` volt

Text Solution

AI Generated Solution

The correct Answer is:
To find the electric potential on the surface of the nucleus of silver, we will use the formula for electric potential \( V \) due to a point charge, which is given by: \[ V = \frac{K \cdot Q}{R} \] Where: - \( V \) is the electric potential, - \( K \) is Coulomb's constant (\( K \approx 9 \times 10^9 \, \text{N m}^2/\text{C}^2 \)), - \( Q \) is the total charge of the nucleus, - \( R \) is the radius of the nucleus. ### Step 1: Determine the charge \( Q \) of the nucleus The charge \( Q \) of the nucleus can be calculated using the atomic number \( Z \) (which is 47 for silver) and the elementary charge \( e \): \[ Q = Z \cdot e = 47 \cdot (1.6 \times 10^{-19} \, \text{C}) \] ### Step 2: Calculate \( Q \) Now, substituting the values: \[ Q = 47 \cdot (1.6 \times 10^{-19}) = 75.2 \times 10^{-19} \, \text{C} = 7.52 \times 10^{-18} \, \text{C} \] ### Step 3: Use the radius \( R \) of the nucleus The radius \( R \) of the nucleus is given as \( 3.4 \times 10^{-14} \, \text{m} \). ### Step 4: Substitute values into the potential formula Now, substituting \( Q \) and \( R \) into the potential formula: \[ V = \frac{K \cdot Q}{R} = \frac{(9 \times 10^9) \cdot (7.52 \times 10^{-18})}{3.4 \times 10^{-14}} \] ### Step 5: Calculate \( V \) Calculating the above expression: \[ V = \frac{(9 \times 10^9) \cdot (7.52 \times 10^{-18})}{3.4 \times 10^{-14}} \] Calculating the numerator: \[ 9 \times 10^9 \cdot 7.52 \times 10^{-18} = 67.68 \times 10^{-9} = 6.768 \times 10^{-8} \] Now, dividing by \( 3.4 \times 10^{-14} \): \[ V = \frac{6.768 \times 10^{-8}}{3.4 \times 10^{-14}} = 1.99 \times 10^6 \, \text{V} \] ### Final Answer Thus, the electric potential on the surface of the nucleus of silver is: \[ V \approx 1.99 \times 10^6 \, \text{V} \]

To find the electric potential on the surface of the nucleus of silver, we will use the formula for electric potential \( V \) due to a point charge, which is given by: \[ V = \frac{K \cdot Q}{R} \] Where: - \( V \) is the electric potential, ...
Promotional Banner

Topper's Solved these Questions

  • ELECTRIC POTENTIAL & CAPACITANCE

    A2Z|Exercise Relation Between Electric Field And Potential|24 Videos
  • ELECTRIC POTENTIAL & CAPACITANCE

    A2Z|Exercise Electric Potential Energy|22 Videos
  • ELECTRIC CHARGE, FIELD & FLUX

    A2Z|Exercise Section D - Chapter End Test|29 Videos
  • ELECTROMAGNETIC INDUCTION

    A2Z|Exercise Section D - Chapter End Test|30 Videos

Similar Questions

Explore conceptually related problems

The electric potential at the surface of an atomic nucleus (Z = 50) of radius 9xx10^(-15)m is

The electric potential at the surface of an atmoic nucleus (Z = 50) of radius 9.0 xx 10^(-13) cm is

The radius of the nucleus with nucleon number 2 is 1.5 xx 10^(-15) m, then the radius of nucleus with nucleon number 54 will be

The nuclear radius of a nucelus with nucleon number 16 is 3 xx 10^(-15) m . Then, the nuclear radius of a nucleus with nucleon number 128 is .

The radius of a nucleus having 10 nucleons is 3 xx 10^(-15) m. The nuclear radius of a nucleus will nucleon number 80 is

An electron is revolving round the nucleus of He^(+) ion with speed 2.2 xx 10^(6) m//s . The potential energy of the electron is (if atomic number of He = 2, 1 eV = 16 xx 10^(-19) J . Mass of electron = 9 xx 10^(-31) kg )

The electric potential on the surface of a sphere of radius R due to a charge 3 xx 10^(-6)C is 500V. The intensity of electric field on the surface of the sphere is (NC^(-1)) is

In an atom electrons revolves around the nucleus along a path of radius 0.72Ã… making 9.4xx 10^(18) revolution per second. The equivalent current is (e=1.6xx10^(-19) C)

Assume that total positive charge of gold nucleus (atomic number, Z = 79) is distributed uniformly in a spherical region of radius 9.6xx10^(-15)m . Calculate electric potential at the surface of this sphere.

A2Z-ELECTRIC POTENTIAL & CAPACITANCE-Section D - Chapter End Test
  1. The radius of nucleus of sliver (atomic number = 47) is 3.4 xx 10^(-14...

    Text Solution

    |

  2. Given: electric potential, phi = x^(2) + y^(2) +z^(2). The modulus of ...

    Text Solution

    |

  3. 125 identical drops each charged to the same potential of 50 volts are...

    Text Solution

    |

  4. Figure shown three points. X, Y and Z forming an equilaternal triangle...

    Text Solution

    |

  5. A point charge is surrounded symmetrically by six identical charges at...

    Text Solution

    |

  6. A charge +Q at A (see figure) produces electric field E and electric p...

    Text Solution

    |

  7. The concentric, thin metallic spheres of radii r(1) and r(2) (r(1) gt ...

    Text Solution

    |

  8. In figure below, the point charge Q(1) causes an electric potential of...

    Text Solution

    |

  9. Two point charges are kept at a certain distance from one another. The...

    Text Solution

    |

  10. A, B, C, D, P, and Q are points in a uniform electric field. The poten...

    Text Solution

    |

  11. Figure shown two equipotential lies x, y plane for an electric field. ...

    Text Solution

    |

  12. An electric dipole is placed along the X-axis O. Point P is at a dista...

    Text Solution

    |

  13. An electric field is given by E(x) = - 2x^(3) kN//C. The potetnial of ...

    Text Solution

    |

  14. All six capacitors shown are identical. Each can withstand maximum 200...

    Text Solution

    |

  15. Two identical parallel plate capacitors are connected in series to a b...

    Text Solution

    |

  16. Five capacitors of 10 muf capacity each are connected to a.d.c potenti...

    Text Solution

    |

  17. A frictionless dielectric plate S is kept on a frictionless table T. A...

    Text Solution

    |

  18. The mean electric energy density between the plates of a charged capac...

    Text Solution

    |

  19. The potentials of the two plates of capacitor are +10V and -10 V. The ...

    Text Solution

    |

  20. Two dielctric slabs of constant K(1) and K(2) have been filled in betw...

    Text Solution

    |

  21. Two parallel plate air filled capacitors, each of capacitacne C are jo...

    Text Solution

    |