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Electric potential at any point is V = -...

Electric potential at any point is `V = - 6x + 2y + 9z`, then the magnitude of the electric field is

A

`3sqrt(2)`

B

`4sqrt(2)`

C

`5sqrt(2)`

D

`11`

Text Solution

Verified by Experts

The correct Answer is:
D
`E_(x) = - (dV)/(dx) = - (-6) = 6,E_(y) = - (dV)/(dy) = -2`
and `E_(z) = - (dV)/(dz) = - 9`
`E_(net) = sqrt(E_(x)^(2) + E_(y)^(2) + E_(z)^(2)) = sqrt(36 + 4 + 81) = sqrt(121) = 11`
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