Figure shown a charged conductor resting on an insulating stand. If at the point `P` the charge density is `sigma`, the potential is `V` and the electric field strength is `E`, what are the values of these quantities at point `Q` ?

Options

A. `{:("Charge density","Potential","Electric intensity"),(gt sigma,gt V,gt E):}`
B. `{:("Charge density","Potential","Electric intensity"),(gt sigma,V,gt E):}`
C. `{:("Charge density","Potential","Electric intensity"),(lt sigma,V,E):}`
D. `{:("Charge density","Potential","Electric intensity"),(lt sigma,V,lt E):}`

Answer

D

Explanation

The surface of the conductor is an equipotential surfaces since is free flow of electrons within the conductor. Thus potential at `Q` is the same as that at `P`. That is `V_(P) = V_(Q) = V`. The electric field `E` at a point on the equipotential surface of the conductor is inversely proportional to the square of theradius of curvature `r` at that point. that is `E prop r^(-2)`
Since point `Q`has a larger radius of curvature then that a point `P`, the electric field at `Q` is less than that at `P`.That is `E_(Q) lt E_(P) = E`.