A sphere of radius `1 cm` has potential of `8000 V`, then energy density near its surface will be

Options

A. `64 xx 10^(5) J//m^(3)`
B. `8 xx 10^(3) J//m^(3)`
C. `32 J//m^(3)`
D. `2.83 J//m^(3)`

Answer

D

Explanation

Energy density `u_(e) = (1)/(2) epsilon_(0)E^(2) = (1)/(2) xx 8.86 xx 10^(-12) xx ((V)/(r ))^(2)`
`= 2.83 J//m^(3)`