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A charge of 10 e.s.u. is palced at a dis...

A charge of `10` e.s.u. is palced at a distance of `2 cm` from a charge of `40` e.s.u and `4 cm` from another charge of `20` e.s.u. The potential energy of the charge `10` e.s.u. is (in ergs)

A

`87.5`

B

`112.5`

C

`150`

D

`250`

Text Solution

Verified by Experts

The correct Answer is:
D

Energy `= (10 xx 40)/(2) + (10 xx 20)/(4) = 250 erg`
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