If `3` charges are placed at the vertices of equilateral triangle of charge 'q' each. What is the net potential energy, if the side of equilateral `Delta` is `l` `cm` ?

Options

A. `(1)/(4pi epsilon_(0))(q^(2))/(l)`
B. `(1)/(4pi epsilon_(0))(2q^(2))/(l)`
C. `(1)/(4pi epsilon_(0))(3q^(2))/(l)`
D. `(1)/(4pi epsilon_(0))(4q^(2))/(l)`

Answer

C

Explanation

`U = (1)/(4pi epsilon_(0)). (Q_(1)Q_(2))/(r )`, net potential energy
`U_("net") = 3 xx (1)/(4pi epsilon_(0)).(q^(2))/(l)`