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A parallel plate condenser is immersed i...

A parallel plate condenser is immersed in an oil of dielectric constant `2`. The field between the plates is

A

increased proportional to `2`

B

decreased proportional to `(1)/(2)`

C

increased proportional to `sqrt(2)`

D

decreased proportional to `(1)/(sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(medium) = (E_(air))/(K) = (E)/(2)`
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Knowledge Check

  • If the gap between the plates of a parallel plate capacitor is filled with medium of dielectric constant k=2 , then the field between them

    A
    Increases by a factor 2
    B
    Increases by a factor `sqrt(2)`
    C
    Decreased by a factor `sqrt(2)`
    D
    Decreased by a factor `1//2`

  • A parallel plate condenser with a dielectric of dielectric constant K between the plates has a capacity C and is charged to a potential V volt. The dielectric slab is slowly removed from between the plates and then reinserted. The net work done by the system in this process is

    A
    (a) zero
    B
    (b) `1/2(K-1)CV^2`
    C
    (c) `(CV^2(K-1))/(K)`
    D
    (d) `(K-1)CV^2`

  • The radius of the circular plates of a parallel plate condenser is 'r' . Air is there as the dielectric. The distance between the plates if its capacitance is equal to that of an isolated sphere of radius r' is.

    A
    `(r^(2))/(4r')`
    B
    `(r^(2))/(r')`
    C
    `( r)/(r')`
    D
    `(r^(2))/(4)`
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