The area of the plates of a parallel plate condenser is `A` and the distance between the plates is `10 mm`. There are two dielectric sheets in it, one of dielectric constant `10` and thickness `6 mm` and the other of dielectric constant `5` and thickness `4 mm`. the capacity of the condenser is

Options

A. `(12)/(35)epsilon_(0)A`
B. `(2)/(3)epsilon_(0)A`
C. `(5000)/(7)epsilon_(0)A`
D. `1500 epsilon_(0)A`

Answer

C

Explanation

`C = (epsilon_(0)A)/(((t_(1))/(k_(1))+(t_(2))/(k_(2)))) = (epsilon_(0)A)/((6 xx 10^(-3))/(10) + (4 xx 10^(-3))/(5)) = (5000)/(7) epsilon_(0) A`