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An air capacitor of capacity C = 10 mu F...

An air capacitor of capacity `C = 10 mu F` is connected to a constant voltage battery of `12 V`. Now the space between the plates is filled with a liquid of dielectirc constant `5`. The charge that flows now from battery to the capacitor is

A

`120 muC`

B

`699 muC`

C

`480 muC`

D

`24 muC`

Text Solution

Verified by Experts

The correct Answer is:
C
Initially charge on the capacitor
`Q = 10 xx 12 = 120 muC`
Finally charge on the capacitor
`Q' = (5 xx 10) xx 12 = 600 muC`
So charge supplied by the battery later
`= Q' - Q = 480 muC`
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