The capacity of a parallel plate capacitor with no dielectric substance but with a separation is reduced to half and it is filled with a dielectirc substance of value `2.8`. The final capacity of the capacitor is

Options

A. `11.2 muF`
B. `15.6 muF`
C. `19.2 muF`
D. `22.4 muF`

Answer

A

Explanation

`C = (epsilon_(0)KA)/(d) rArr (C_(1))/(C_(2)) = (K_(1))/(K_(2)) xx (d_(2))/(d_(1))`
`(2)/(C_(2)) = (1)/(2.8) xx ((0.4//2))/((0.4)) rArr C_(2) = 11.2 muF`