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To obtain 3 mF capacity from three capac...

To obtain `3 mF` capacity from three capacitors of `2mF` each, they will be arranged

A

All the three in series

B

All the three in parallel

C

Two capacitors in series and the third in parallel with the combination of first two

D

Two capacitors in parallel and the third in series with the combination of first two

Text Solution

Verified by Experts

The correct Answer is:
C
`C = (2xx2)/(2+2) +2 = 3muF`
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A2Z-ELECTRIC POTENTIAL & CAPACITANCE-Capacitor Circuits
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