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In the given network capacitance, C(1) =...

In the given network capacitance, `C_(1) = 10muF, C_(2) = 5 muF` and `C_(3) = 4muF`. What is the resultant capacitance between `A` and `B`?

A

`2.2 muF`

B

`3.2 muF`

C

`1.2 muF`

D

`4.7 muF`

Text Solution

Verified by Experts

The correct Answer is:
B

`C = ((C_(1)+C_(2))xxC_(3))/((C_(1) + C_(2))+C_(3)) = ((5 + 10) xx 4)/(5 + 10 +4) = (60)/(19) = 3.2 muF`
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