Two capacitors `A` and `B` are connected in series with a battery as shown in the figure. When the switch `S` is closed and the two capacitors get charged fully, then

Options

A. The potential difference across the plates of `A` is `4 V` and across the plates of `B` is `6V`
B. The potential difference across the plates of `A` is `6V` and across the plates of `B` is `4V`
C. The ratio of electrical energies stored in `A` and `B` is `2:3`
D. The ratio of charges on `A` and `B` is `3:2`

Answer

B

Explanation

In series combination of capacitors, voltage distributes on them, in the reverse ratio of their capacitance i.e.,
`(V_(A))/(V_(B)) = (3)/(2)` ..(i)
Also `V_(A) + V_(B) = 10` ..(ii)
On solving (i) and (ii) `V_(A) = 6V, V_(B) = 4V`