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A 5C charge experience a force of 2000 N...

A `5C` charge experience a force of `2000 N` when moved between two points separated by a distance of `2 cm` in a uniform electric field. The potential difference between the two points is

A

`8 V`

B

`200 V`

C

`800 V`

D

`20000 V`

Text Solution

Verified by Experts

The correct Answer is:
A

`E = (2000)/(5)NC^(-1) = 400 NC^(-1)`
Now, `V = Er = 400 xx (2)/(100)V = 8V`
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