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Find out work done by electirc field in ...

Find out work done by electirc field in shifting a point charge `(4sqrt(2))/(27)muC` from point `P` to `S` which are shown in the figure:

A

`(100)/(3)J`

B

`(200)/(3)J`

C

`100 J`

D

`200 J`

Text Solution

Verified by Experts

The correct Answer is:
A
Work done by electirc field:
`W = PE_(i) - PE_(f) = q[V_(i) - V_(f)]`
`= q[(kp cos 45^(@))/((1 xx 10^(-2))^(2)) - (kp cos 135^(@))/((2 xx 10^(-2))^(2))]`
Here, `q = (4sqrt(2))/(27) muC` and `p = 2 xx 10^(-6) C_(-m)`
`:.` Work done `= (100)/(3) J`
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