A capacity of capacity `C_(1)` is charged up to `V` volt and then connected to an uncharged capacitor of capacity `C_(2)`. Then final potential difference across each will be

Options

A. `(C_(2)V)/(C_(1)+C_(2))`
B. `(1+(C_(2))/(C_(2)))V`
C. `(C_(1)V)/(C_(1)+C_(2))`
D. `(1-(C_(2))/(C_(1)))V`

Answer

C

Explanation

Common potential `V' = (C_(1)V + C_(2) xx 0)/(C_(1)+C_(2)) = (C_(1))/(C_(1)+C_(2)).V`