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Three plates of common surface area A ar...

Three plates of common surface area `A` are connected as shown. The effective capacitance will be

A

`(epsilon_(0)A)/(d)`

B

`(3epsilon_(0)A)/(d)`

C

`(3)/(2)(epsilon_(0)A)/(d)`

D

`(2epsilon_(0)A)/(d)`

Text Solution

Verified by Experts

The correct Answer is:
D
The given circuit is equivalent to parallel combination of two identical capacitors, each having capacitance
`C = (epsilon_(0)A)/(d)`. Hence `C_(eq) = 2C = (2epsilon_(0)A)/(d)`
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