The capacity of a parallel plate condenser is `10 muF` without dielectric. Dielectric of constant `2` is used to fill half the distance between the plates, the new capacitance in `muF` is

Options

A. `10`
B. `20`
C. `15`
D. `13.33`

Answer

D

Explanation

`C = (A epsilon_(0))/(d) = 10muF`
`C_(1) = (A epsilon_(0))/(d - t+(t)/(k)) = (A epsilon_(0))/(d - (d)/(2) + (d)/(2k))`
`= (A epsilon_(0))/((d)/(2)(1+(1)/(2))) = (4)/(3). (A epsilon_(0))/(d)`
`:. C_(1) = (4)/(3) xx 10 = 13.33 muF`