All six capacitors shown are identical. Each can withstand maximum `200` volts between its terminals. The maximum voltage that can be safely applied between `A` and `B` is

Options

A. `1200 V`
B. `400 V`
C. `800 V`
D. `200 V`

Answer

B

Explanation

Given circuit can be reduced as follows
`(C =` capacitance of each capacitor)
The capacitor `3C, 3C` shown in figure can withstand maximum `200 V`.
`:.` So maximum voltage that can be applied across `A` and `B` eqully shared. Hence maximum voltage applied cross `A` and `B` be equally shared. hence max. voltage applied across `A` and `B` will be `(200 + 200) = 400` volt.