Two rods of same material and length have their electric resistance in ratio `1 : 2`. When both rods are dipped in water, the correct statement will be

Options

A. `A` has more loss of weight
B. `B` has more loss of weight
C. Both have same loss of weight
D. Loss of weight will be in the ratio `1 : 2`

Answer

A

Explanation

(a) `R = rho (l)/(A) implies (R_(1))/(R_(2)) = (A_(2))/(A_(1)) (rho, L "constant") implies (A_(1))/(A_(2)) = (R_(2))/(R_(1)) = 2`
Now, when a body dipped in water, loss of weigh `V sigma_(L) g Al sigma_(L) g`
So, `(("Loss of weigth")_(1))/(("Loss of wight")_(2)) = (A_(1))/(A_(2)) = 2`, so `A` has more loss of weight.