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The length of the resistance wire is inc...

The length of the resistance wire is increased by `10%`. What is the corresponding change in the resistance of wire?

A

`10%`

B

`25%`

C

`21%`

D

`9%`

Text Solution

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The correct Answer is:
To solve the problem of how the resistance of a wire changes when its length is increased by 10%, we can follow these steps: ### Step-by-Step Solution: 1. **Assume Initial Length**: Let's assume the initial length of the wire, \( L_i \), is 100 units. This makes calculations easier when dealing with percentages. **Hint**: Always start with a convenient value for initial conditions to simplify calculations. 2. **Calculate Final Length**: Since the length is increased by 10%, the final length \( L_f \) can be calculated as: \[ L_f = L_i + 10\% \text{ of } L_i = 100 + 10 = 110 \text{ units} \] **Hint**: To find the final value after a percentage increase, add the percentage of the initial value to the initial value. 3. **Understand Resistance Relation**: The resistance \( R \) of a wire is directly proportional to its length when other factors (like material and cross-sectional area) remain constant. Thus, we can express this relationship as: \[ R \propto L \] 4. **Calculate Initial and Final Resistance**: Let the initial resistance be \( R_i \). The final resistance \( R_f \) can be expressed as: \[ \frac{R_f}{R_i} = \frac{L_f}{L_i} = \frac{110}{100} = 1.1 \] Therefore, the final resistance can be expressed as: \[ R_f = R_i \times 1.1 \] **Hint**: When dealing with proportional relationships, set up a ratio to find the new value based on the change. 5. **Calculate Change in Resistance**: The change in resistance \( \Delta R \) is given by: \[ \Delta R = R_f - R_i = (1.1 R_i - R_i) = 0.1 R_i \] **Hint**: The change in a quantity can be found by subtracting the initial value from the final value. 6. **Calculate Percentage Change in Resistance**: The percentage change in resistance can be calculated using the formula: \[ \text{Percentage Change} = \left( \frac{\Delta R}{R_i} \right) \times 100 = \left( \frac{0.1 R_i}{R_i} \right) \times 100 = 10\% \] **Hint**: To find the percentage change, divide the change by the original value and multiply by 100. ### Final Answer: The corresponding change in the resistance of the wire when its length is increased by 10% is **10%**.

To solve the problem of how the resistance of a wire changes when its length is increased by 10%, we can follow these steps: ### Step-by-Step Solution: 1. **Assume Initial Length**: Let's assume the initial length of the wire, \( L_i \), is 100 units. This makes calculations easier when dealing with percentages. **Hint**: Always start with a convenient value for initial conditions to simplify calculations. ...
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A2Z-CURRENT ELECTRICITY-Section D - Chapter End Test
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