The current in the adjoining circuit will be

Options

A. `(1)/(45) ampere`
B. `(1)/(15) ampere`
C. `(1)/(10) ampere`
D. `(1)/(5) ampere`

Answer

C

Explanation

(c ) `R_(e q u i v a l e n t) = ((30 + 30) 30)/((30 + 30) 30) = (60 xx 30)/(90) = 20 Omega`
`:. i= (V)/(R ) = (2)/(20) = (1)/(10)` ampere