In circuit shown below, the resistance are given in ohms and the battery is assumed ideal with emf equal to 3 volt The voltage across the resistance `R_(4)` is

Options

A. `0.4 V`
B. `0.6 V`
C. `1.2 V`
D. `1.5 V`

Answer

A

Explanation

(a) Equivalent resistance of the given network `R_(eq) = 75 Omega`
`:.` Total current through battery `i= (3)/(75)`
`i_(1) = i_(2) = (3)/(75 xx 2) = (3)/(150)`
Current through `R_(4) = (3)/(150) xx (60)/((30 + 60))`
`= (3)/(150) xx (60)/(90) = (2)/(150) A`
`V_(4) = i_(4) xx R_(4) = (2)/(150) xx 30 = (2)/(5) V = 0.4 V`