Two batteries of e.m.f. `4V` and `8V` with internal resistances `1 Omega` and `2 Omega` are connected in a circuit with a resistance of `9 Omega` as shown in figure. The current and potential difference between the points `P` and `Q`

Options

A. `(1)/(3) A` and `3 V`
B. `(1)/(6) A` and `4 V`
C. `(1)/(9) A` and `9 V`
D. `(1)/(2) A` and `12 V`

Answer

A

Explanation

(a) Applying Kirchhoff's voltage law in the given loop.
`- 2i + 8 - 4 - 1 xx I = 0 implies I = (1)/(3) A`
Potential difference across `PQ = (1)/(3) xx 9 = 3 V`