Find current in the branch `CD` of the circuit

Options

A. `15 A`
B. `35 A`
C. `10 A`
D. `25 A`

Answer

A

Explanation

(a) Circuit can be redrawn as
`R_(eq) = (3)/(2) Omega, I = (V)/(R_(eq)) = 20 A`
Current In `I_(CD) = I_(AC) + I_(B) , I_(CD) = 15 A`