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A circuit is arranged as shown. Then, th...

A circuit is arranged as shown. Then, the current from `A` to `B` is

A

`+ 500 mA`

B

`+ 1.5 mA`

C

`- 250 mA`

D

`- 500 mA`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) `I = (sum (E // r))/(1 + R sum (1//r))`
`= ((5)/(15) + (10)/(10))/(1 + 10 [ (1)/(15) + (1)/(10)]) = (1)/(2) A = 500 mA`
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