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The energy stored in the capacitor in th...

The energy stored in the capacitor in the steady state is

A

`338 mu J`

B

`196 mu J`

C

`98 mu J`

D

`8 mu J`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) `V_(A) + 3 xx 1 - 14 - 5 xx 3V_(B)`
`implies V_(A) - V_(B) = 26 V`
Energy stored in capacitor
`U = (1)/(2) CV^(2) = (1)/(2) xx (10^(-6)) xx (26)^(2) = 338 mu J`
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