A galvanometer has a resistance of `25 ohm` and a maximum of `0.01 A` current can be passed through it. In order to change it into an ammeter of range `10 A`, the shunt resistance required is

Options

A. `5//999 ohm`
B. `10//999 ohm`
C. `20//999 ohm`
D. `25//999 ohm`

Answer

D

Explanation

(d) `i_(g) = i(S)/(G + S) implies 0.01 = 10 (S)/(24 + S)`
`implies 1000 S = 25 + S implies S = (25)/(999) Omega`