A galvanometer coil has a resistance `90 Omega` and full scale deflection current `10 mA`. A `910 Omega` resistance is connected in series with the galvanometer to make a voltmeter. If the least count of the voltmeter is `0.1 V` the number of divisions on its scale is

Options

A. 90
B. 91
C. 100
D. None

Answer

C

Explanation

(c ) `R_(v) = (V)/(i_(g)) - G implies 910 = (V)/(10 xx 10^(-3)) = 90`
`implies V = 10 implies` No. of division `= (10)/(0.12) = 100`