In a potentiometer experiment it is found that no current passes through the galvanometer when the terminals of the cell are connected across `0.52 m` of the potentiometer wire. If the cell is shunted by a resistance of `5Omega` balance is obtained when the cell connected across` 0.4m` of the wire. Find the internal resistance of the cell.

Options

A. `0.5 Omega`
B. `1 Omega`
C. `1.5 Omega`
D. `2 Omega`

Answer

C

Explanation

(c ) `r = [(l_(1))/(l_(2)) - 1] = 5 [(0.52)/(0.4) - 1] = 5 [1.3 - 1] = 1.5 Omega`