A resistor `R_(1)` dissipates the power `P` when connected to a certain generator. If the resistor `R_(2)` is put in series with `R_(1)`, the power dissipated by `R_(1)`

Options

A. Decreases
B. Increases
C. Remains the same
D. Any of the above depending upon the relative values of `R_(1)` and `R_(2)`

Answer

A

Explanation

(a) Equivalent resistance in the second case` = R_(1) + R_(2) = R`
Now, we know that `P prop (1)/(R )`
Since in the second case the resistance `(R_(1) + R_(2))` is higher than that in the first case `(R_(1))`.
Therefore power dissipation in the second case will be decreased.