A 100 watt bulbe working on 200 volt and a 200 watt bulb working on 100 volt have

Options

A. Resistance in the ratio of `4:1`
B. Maximum current ratings in the ratio of `1:4`
C. Resistance in the ratio of `2:1`
D. Maximum current ratings in the ratio of `1:2`

Answer

B

Explanation

(b) `R = (V^(2))/(P) implies R_(1) = (200 xx 200)/(10) = 400 Omega`
`R_(2) = (100 xx 100)/(200) = 50 Omega` Maximum current rating
`I = (P)/(V)`
So `i_(1) = (100)/(200)` and `i_(2) = (200)/(100) implies (i_(1))/(i_(2)) = (1)/(4)`