In the circuit shown in fig the heat produced in the 5 ohm resistor due to the current flowing through it is 10 calories per second.

The heat generated in the 4 ohms resistor is

Options

A. `1 cal/sec`
B. `2 cal/sec`
C. `3 cal/sec`
D. `4 cal/sec`

Answer

B

Explanation

(b) `(i_(1))/(i_(2)) = (R_(2))/(R_(1)) = (10)/(5) = (2)/(1)`
Also heat produced per sec i.e., `(H)/(t) = P i^(2) R`
`implies (P_(5))/(P_(4)) = ((i_(1))/(i_(2)))^(2) xx (5)/(4) = ((2)/(1))^(2) xx (5)/(4) = (5)/(1) implies P_(4) = (10)/(5) = 2 cal//s`