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Two sources of equal emf are connected t...

Two sources of equal emf are connected to an external resistance R. The internal resistance of the two sources are `R_1 and R_2(R_1gtR_1).` if the potential difference across the source having internal resistance `R_2` is zero, then

A

`R = R_(1) R_(2) // (R_(1) + R_(2))`

B

`R = R_(1) R_(2) // (R_(1) - R_(2))`

C

`R = R_(2) xx (R_(1) + R_(2)) // (R_(2) - R_(1))`

D

`R = R_(2) - R_(1)`

Text Solution

Verified by Experts

The correct Answer is:
D

(d) `i= (2E)/(R + R_(1) + R_(2))`
From cell (2) `E = V + iR_(2) = 0 + iR_(2)`
`implies E = (2E)/(R + R_(1) + R_(2)) xx R_(2) implies R = R_(2) - R_(1)`
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