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Magnetic field at the centre of coil of ...

Magnetic field at the centre of coil of `n` turns, bent in the form of a square of side `2l`, carrying current `i`, is

A

`0.5xx10^(-5) T`

B

`1.25xx10^(-4) T`

C

`3.0xx10^(-5) T`

D

`4xx10^(-5) T`

Text Solution

Verified by Experts

The correct Answer is:
B
`B=(mu_(0)Ni)/(2r) =(4pixx10^(-7)xx50xx2)/(2xx0.5) =1.25xx10^(-4)T`
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