A particle of mass `m` and charge `q` travelling at a velocity `v` along `x`-axis at time `t=0`. It enters a region in which electric field, `E` is present along `z`-axis and magnetic field, `B` is present along `y`-axis. The distance covered upto time `t=0.2xx10^(-1) sec,` along `x`-axis is `v//50` (in meters). find the value of `v`:

Options

A. `(50 E)/B`
B. `E/(50 B)`
C. `E/(20B)`
D. `E/B`

Answer

D

Explanation

Distance covered in time `t=v//50` (given)
From, `x=vt=vxx0.02=v//50`
Thus, acceleration of particle `=0`
So, `F_("net")=0`
`F_(e)=F_(m)`
`qE=qvB`
`v=(E )/(B)`