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When a charged particle moving with vel...

When a charged particle moving with velocity `vec(V)` is subjected to a magnetic field of induction `vec(B)` the force on it is non-zero. This implies that:

A

angle between `vec(V)` and `vec(B)` is necessarily `90^(@)`

B

angle between `vec(V)` and `vec(B)` can have any value other than `90^(@)`

C

angle between `vec(V)` and `vec(B)` can have any value other than zero to `180^(@)`

D

angle between `vec(V)` and `vec(B)` is either zero to `180^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C

When a charged particle `q` is moving in a uniform magnetic field `vec(B)` with velocity `vec(V)` such that angle between `vec(V)` and `vec(B)` be `theta`, then due to interaction between the magnetic field produced due to moving charge and magnetic field applied, the charge `q` experience a force which is given by
`F=qvB sin theta`
If `theta=0^(@)` or `180^(@)`, then `sin theta=0`
`:. F=qv B sin theta =0`
Since, force on charged particle is non-zero, so angle between `vec(V)` and `vec(B)` can have any value other than zero and `180^(@)`.
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